Use the given frequency distribution to find the
(a)class width.
(b)class midpoints of the first class.
(c)class boundaries of the first class.
-$$\begin{array}{l}
\text { Miles (per day) }\
\begin{array} { c | c }
\text { Class } & \text { Frequency, } \mathrm { f } \
\hline 1 - 2 & 9 \
3 - 4 & 22 \
5 - 6 & 28 \
7 - 8 & 15 \
9 - 10 & 4
\end{array}
\end{array}$$ 2 8
5
A) (a) 2
(b) $1.5$
(c) $0.5 - 2.5$
B) (a) 1
(b) $1.5$
(c) $0.5 - 2.5$
C) (a) 2
(b) 1
(c) $1 - 2$
D) (a) 1
(b) 1
(c) 1-2

Question

Use the given frequency distribution to find the
(a)class width.
(b)class midpoints of the first class.
(c)class boundaries of the first class.
-$$\begin{array}{l}
\text { Miles (per day) }\
\begin{array} { c | c } 
\text { Class } & \text { Frequency, } \mathrm { f } \
\hline 1 - 2 & 9 \
3 - 4 & 22 \
5 - 6 & 28 \
7 - 8 & 15 \
9 - 10 & 4
\end{array}
\end{array}$$ 2 8
5
A) (a) 2
(b) $1.5$
(c) $0.5 - 2.5$
B) (a) 1
(b) $1.5$
(c) $0.5 - 2.5$
C) (a) 2
(b) 1
(c) $1 - 2$
D) (a) 1
(b) 1
(c) 1-2

Quizplus · Accepted Answer

The class width is found by subtracting the lower limit of the first class from the lower limit of the second class, which is $3 - 1 = 2$. The midpoint of the first class is the average of its upper and lower limits, which is $(1 + 2) / 2 = 1.5$. The class boundaries of the first class are found by subtracting 0.5 from the lower limit and adding 0.5 to the upper limit, resulting in $0.5 - 2.5$.

Use the Given Frequency Distribution to Find the (A)class Width

Use the Given Frequency Distribution to Find the
(A)class Width