Solve the problem.
-A velocitycity $\geq 0$ 0 indicates that the object is traveling upward and a velocityelocity $\leq 0$ in idicates that the object is traveling downward. An object is projected upward andand v(t) $\mathrm { v } ( \mathrm { t } ) = - 9 \mathrm { t } + 55.8,0 \leq \mathrm { t } \leq 12$ 12. Determi. Determne the interval when the
Object is traveling downward.
A) $[ 5.2,9.2 ]$
B) $[ 0,6.2 ]$
C) $[ 6.2,12 ]$
D) $[ 6.2,9 ]$

Question

Quizplus · Accepted Answer

The object is traveling downward when $v(t) \leq 0$. Setting the velocity equation to less than or equal to zero, $-9t + 55.8 \leq 0$, solving for $t$ gives $t \geq 6.2$. Thus, the object is traveling downward from $t = 6.2$ to $t = 12$, which corresponds to choice C: $[6.2, 12]$.

Solve the Problem ≥0\geq 0≥0 0 Indicates That the Object Is Traveling Upward and a the Object

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