Solve the problem.
-A landscaping company sells 30-pound bags of top soil. The actual weight x of a bag, however, may differ from the advertised weight by as much as 0.75 pound. The actual weight of the bag of topsoil, x, can be described by
The inequalityy $| x - 30 | \leq 0.75$ . Gi Gve the solution of the inequality in interval notation.
A)[29.25, 30.75]
B)[-29.25, 30.75]
C) $( \infty , 29.25 ] \cup [ 30.75 , \infty )$
D)(29.25, 30.75)

Question

Quizplus · Accepted Answer

The inequality $| x - 30 | \leq 0.75$ describes the range of actual weights x that are within 0.75 pounds of the advertised weight of 30 pounds. Solving this inequality, we find that the actual weight x must be between 29.25 and 30.75 pounds, inclusive. Therefore, the solution in interval notation is [29.25, 30.75].

Solve the Problem ∣x−30∣≤0.75| x - 30 | \leq 0.75∣x−30∣≤0.75 Gi Gve the Solution of the Inequality in Interval

Solve the Problem $| x - 30 | \leq 0.75$ Gi Gve the Solution of the Inequality in Interval