Solve the problem.
-In a Power Ball lottery, 5 numbers between 1 and 12 inclusive are drawn. These are the winning numbers. How many different selections are possible? Assume that the order in which the numbers are drawn is not important.
A) 248,832
B) 792
C) 95,040
D) 120

Question

Quizplus · Accepted Answer

The number of different selections possible is calculated using the combination formula, which is C(n, r) = n! / [r!(n - r)!], where n is the total number of items, and r is the number of items to be chosen. Here, n = 12 (numbers 1 through 12) and r = 5 (choosing 5 numbers). Thus, the calculation is C(12, 5) = 12! / [5!(12 - 5)!] = 12! / (5!7!) = 792.

Solve the Problem. -In a Power Ball Lottery, 5 Numbers Between 1 and Between