Factor completely.
-xy - 2yz + 4x - 8z
A) (y + 4)(x - 2z)
B) (y + 2)(x - 4z)
C) (y - 2)(x + 4z)
D) (y - 4)(x + 2z)

Name: Factor completely. -xy - 2yz + 4x - 8z A) (y + 4)(x - 2z) B) (y + 2)(x - 4z) C) (y - 2)(x + 4z) D) (y - 4)(x + 2z)
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Question

Quizplus · Accepted Answer

The expression can be factored by grouping: xy - 2yz + 4x - 8z = y(x - 2z) + 4(x - 2z) = (y + 4)(x - 2z).

Factor Completely. -Xy - 2yz + 4x - 8z