Solve the problem.
-The winning times (in seconds) in a speed-skating event for men can be represented by the expression 46.77 - 0.091x, where x represents the year, with x = 0 corresponding to 1920. (For example in 1992, x would be
1992 - 1920 = 72.) What would the winning time in 1950 be according to the model? Round your answer to the
Nearest hundredth.
A) 45.86 sec
B) 44.95 sec
C) 1400.37 sec
D) 44.04 sec

Question

Quizplus · Accepted Answer

To find the winning time in 1950, we need to substitute x=1950-1920=30 into the expression 46.77-0.091x:
winning time = 46.77 - 0.091(30) 
winning time = 46.77 - 2.73
winning time ≈ 44.04 sec (rounded to the nearest hundredth)
Therefore, the best choice is D, 44.04 sec.

Solve the Problem. -The Winning Times (In Seconds) in a Speed-Skating Event for Speed-Skating