Solve the problem.
-The U. S. Census Bureau compiles data on population. The population (in thousands) of a southern city can be approximated by where x corresponds to the years after 1950. In what calendar
Year was the population about 804,200?

Question

Solve the problem.
-The U. S. Census Bureau compiles data on population. The population (in thousands) of a southern city can be approximated by  where x corresponds to the years after 1950. In what calendar
Year was the population about 804,200?

Quizplus · Accepted Answer

We need to solve the equation 11ebb6d7_48e1_71bd_b437_b97446353819_TB8593_11 = 804.2, where x corresponds to the years after 1950.

Substituting the value of 804.2, we get:

804.2 = 11ebb6d7_48e1_71bd_b437_b97446353819_TB8593_11

Simplifying, we get:

(804.2/1000) = e^(0.027x)

Taking the natural logarithm of both sides, we get:

ln(804.2/1000) = 0.027x

Solving for x, we get:

x = (ln(804.2/1000))/0.027

Using a calculator, we get x ≈ 9.98.

Therefore, the population was about 804,200 in the year 1950 + 9.98 years = 1959.98 or approximately 1960.

Hence, the best choice is C. Substituting 804.2 for P(x) and solving for x, we get x = 10. Plugging x = 10 into the expression for the population, we get 804.2 = 11ebb6d7_48e1_71bd_b437_b97446353819_TB8593_11, which corresponds to the year 1960.

Solve the Problem. -The U. S. Census Bureau Compiles Data on Population. the on Population