Solve.
-x + 5y + 2z = 1 3y + 4z = -2
Z = -2

Question

Quizplus · Accepted Answer

The system of equations given is underdetermined (meaning there are more variables than equations), so typically, there would be an infinite number of solutions depending on the values of the free variables. However, since a specific value for $z$ is given ($z = -2$), we can substitute this value into the second equation to find $y$, and then use both $y$ and $z$ values to find $x$ from the first equation.Substituting $z = -2$ into the second equation:$$3y + 4(-2) = -2$$$$3y - 8 = -2$$$$3y = 6$$$$y = 2$$Now, substituting $y = 2$ and $z = -2$ into the first equation:$$x + 5(2) + 2(-2) = 1$$$$x + 10 - 4 = 1$$$$x + 6 = 1$$$$x = -5$$Therefore, the solution is $x = -5$, $y = 2$, and $z = -2$, which corresponds to choice B $(-5, 2, -2)$.

Solve. -X + 5y + 2z = 1 3y + 4z