Find the real solutions, if any, of the equation. Use the quadratic formula.
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Question

Quizplus · Accepted Answer

Since we are given the quadratic equation in standard form $ax^2 + bx + c = 0$, where $a=1$, $b=6$, and $c=5$, we can use the quadratic formula: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ Substituting our values, we get: $$x = \frac{-6 \pm \sqrt{(6)^2 - 4(1)(5)}}{2(1)}$$ Simplifying: $$x = \frac{-6 \pm \sqrt{16}}{2}$$ $$x = \frac{-6 \pm 4}{2}$$ Therefore, the solutions are: $$x = -5 	ext{ and } x = -1$$ Thus, the correct choice is A.

Find the Real Solutions, If Any, of the Equation