Solve the problem.
-How many gallons of a 30% alcohol solution must be mixed with 60 gallons of a 14% solution to obtain asolution that is 20% alcohol?
A)36 gal
B)27 gal
C)7 gal
D)12 gal

Question

Quizplus · Accepted Answer

To find the number of gallons of the 30% solution needed, set up the equation: 0.30x + 0.14(60) = 0.20(x + 60). Solving for x gives x = 36 gallons.

Solve the Problem. -How Many Gallons of a 30% Alcohol Solution Must Be