Solve the problem.
-How many liters of 80% hydrochloric acid must be mixed with 40% hydrochloric acid to get 15 liters of65% hydrochloric acid? Write your answer rounded to three decimals.
A)9.375 L
B)3.125 L
C)4.688 L
D)8 L

Question

Quizplus · Accepted Answer

To solve this problem, we can use the concept of weighted averages or the method of alligation. Let $x$ be the amount of 80% hydrochloric acid and $15 - x$ be the amount of 40% hydrochloric acid. The equation to represent the mixture is: $0.8x + 0.4(15 - x) = 0.65 \times 15$. Solving for $x$ gives $x = 9.375$ liters.

Solve the Problem. -How Many Liters of 80% Hydrochloric Acid Must Be Mixed