Solve the problem.
-The perimeter of a rectangle is 66 m. If the width were doubled and the length were increased by 24 m, the perimeter would be 132 m. What are the length and width of the rectangle?
A) width 16 m, length 16 m
B) width 11 m, length 16 m
C) width 24 m, length 9 m
D) width 9 m, length 24 m

Question

Quizplus · Accepted Answer

The original perimeter is 2(length + width) = 66 m. If the width is doubled and the length increased by 24 m, the new perimeter becomes 2(2*width + length + 24) = 132 m. Solving these equations, we find the width = 9 m and length = 24 m.

Solve the Problem. -The Perimeter of a Rectangle Is 66 M. If the M