Solve the problem.
-Michael's bank contains only nickels, dimes, and quarters. There are 56 coins in all, valued at $4.95. The number of nickels is 8 short of being three times the sum of the number of dimes and quarters together. How many
Dimes are in the bank?
A) 40 dimes
B) 7 dimes
C) 12 dimes
D) 9 dimes

Question

Quizplus · Accepted Answer

Let the number of dimes be $d$, quarters be $q$, and nickels be $n$. We have three equations based on the problem statement:1. $n + d + q = 56$ (total number of coins)2. $0.05n + 0.10d + 0.25q = 4.95$ (total value of coins)3. $n = 3(d + q) - 8$ (relationship between nickels, dimes, and quarters)Substituting $n$ from equation 3 into equation 1 gives us a system of two equations with two unknowns ($d$ and $q$). Solving this system reveals that there are 7 dimes in the bank.

Solve the Problem. -Michael's Bank Contains Only Nickels, Dimes, and Quarters. There Are