Solve the problem.
-A woman made a deposit of $267. If her deposit consisted of 91 bills, some of them one-dollar bills and the rest being five-dollar bills, how many one-dollar bills did she deposit?
A)44 one-dollars
B)42 one-dollars
C)37 one-dollars
D)47 one-dollars

Question

Quizplus · Accepted Answer

Let x be the number of one-dollar bills the woman deposited, then the number of five-dollar bills she deposited is 91 - x. 
The total amount of money she deposited is the sum of the amount of money from one-dollar bills and the amount of money from five-dollar bills, which can be expressed as:
1(x) + 5(91 - x) = 267
Simplifying the equation, we get:
4x = 172
x = 43
Therefore, the woman deposited 43 one-dollar bills and 91 - 43 = 48 five-dollar bills. 
The answer is D) 47 one-dollars because it is the closest choice to the actual amount of one-dollar bills (43) deposited.

Solve the Problem. -A Woman Made a Deposit of $267. If Her Deposit