Solve.
-The pitch P of a musical tone varies inversely as its wavelength W. One tone has a pitch of 482 vibrations per second and a wavelength of 12 ft. Find the wavelength of another tone that has a pitch of 348 vibrations per
Second. Round to the nearest hundredths when necessary.
A) 0.06 ft
B) 13,978 ft
C) 16.62 ft
D) 1.66 ft

Question

Quizplus · Accepted Answer

The relationship between pitch (P) and wavelength (W) is inversely proportional, so $P = k/W$, where $k$ is a constant. For the first tone, $482 = k/12$, so $k = 482 \times 12$. For the second tone with a pitch of 348 vibrations per second, $348 = (482 \times 12)/W$. Solving for $W$ gives $W \approx 16.62$ ft.

Solve. -The Pitch P of a Musical Tone Varies Inversely as as Its