Superimposing an AC voltage of 3.54 Vrms with a DC source of 10 V results in a waveform that:
A)peaks at 15 V.
B)peaks at 13.54 V.
C)peaks at 20 V.
D)both B and C

Name: Superimposing an AC voltage of 3.54 Vrms with a DC source of 10 V results in a waveform that: A)peaks at 15 V. B)peaks at 13.54 V. C)peaks at 20 V. D)both B and C
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Question

Quizplus · Accepted Answer

The peak value of the AC voltage is 3.54 Vrms * √2 ≈ 5 V. Adding this to the 10 V DC source results in a waveform that peaks at 15 V.

Superimposing an AC Voltage of 3