Acetylene (C₂H₂)burns in pure oxygen with a very hot flame.The products of this reaction are carbon dioxide and water.How much oxygen is required to react with 52.0 g of acetylene?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the combustion of acetylene in oxygen is:

C₂H₂ + 2.5 O₂ → 2 CO₂ + H₂O

This means that 2.5 moles of oxygen are required to react with each mole of acetylene. To calculate the amount of oxygen required to react with 52.0 g of acetylene, we can set up the following calculation:

52.0 g C₂H₂ x (1 mol C₂H₂/26.04 g) x (2.5 mol O₂/1 mol C₂H₂) x (32.00 g O₂/1 mol O₂) = 160 g O₂

Therefore, the answer is (C) 160.0 g.

Acetylene (C₂H₂)burns in Pure Oxygen with a Very Hot Flame