Recall that Hubble's law is written v = H₀d,where v is the recession velocity of a galaxy located a distance d away from us,and H₀ is Hubble's constant.Suppose H₀ = 65 km/s/Mpc.How fast would a galaxy located 500 megaparsecs distant be receding from us?
A)65 km/s
B)65 Mpc/s
C)32,500 km/s
D)9 km/s
E)0.65 times the speed of light

Question

Quizplus · Accepted Answer

Given: H₀ = 65 km/s/Mpc, d = 500 megaparsecs.

Using the formula v = H₀d, we can find the recession velocity of the galaxy.

v = H₀d
v = (65 km/s/Mpc)(500 Mpc)
v = 32,500 km/s

Therefore, the galaxy located 500 megaparsecs distant would be receding from us at a velocity of 32,500 km/s.

Recall That Hubble's Law Is Written V = H₀d,where V