If 225.6 grams of silver chloride are produced in a precipitation reaction, how many moles of the salt have been formed?

Question

Quizplus · Accepted Answer

To find the number of moles of silver chloride (AgCl) formed, use the molar mass of AgCl (107.87 g/mol for Ag + 35.45 g/mol for Cl = 143.32 g/mol for AgCl). Divide the mass of AgCl formed (225.6 g) by its molar mass (143.32 g/mol): 225.6 g / 143.32 g/mol = 1.574 moles, which corresponds to choice A.

If 2256 Grams of Silver Chloride Are Produced in a Precipitation