Given that: 3 NO₂( g ) + H₂O( l ) → 2 HNO₃( aq )+ NO( g ), what quantity (L) of NO₂ is required to completely react 125 grams of water. Assume that the gases are at standard temperature and pressure and hence 1.00 mole occupies 22.4 L of volume.

Question

Quizplus · Accepted Answer

To find the volume of NO₂ required, first calculate the moles of water: 125 g H₂O / 18 g/mol = 6.94 mol H₂O. From the balanced equation, 3 moles of NO₂ react with 1 mole of H₂O, so 6.94 mol H₂O requires 3 * 6.94 = 20.82 mol NO₂. At STP, 1 mole of gas occupies 22.4 L, so 20.82 mol NO₂ * 22.4 L/mol = 466 L NO₂.

Given That: 3 NO2( G ) + H2O( L )

Given That: 3 NO₂( G ) + H₂O( L )