If 8.42 × 10^{− 2} moles of aluminum react with 1.77 × 10^{− 2} moles of chlorine gas, how many moles of AlCl₃ may form?

Name: If 8.42 × 10 − 2 moles of aluminum react with 1.77 × 10 − 2 moles of chlorine gas, how many moles of AlCl 3 may form?
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Quizplus · Accepted Answer

The balanced chemical equation for the reaction is 2Al + 3Cl₂ → 2AlCl₃. The limiting reactant is Cl₂, and using stoichiometry, 1.77 × 10⁻² moles of Cl₂ will produce 1.18 × 10⁻² moles of AlCl₃.

If 842 × 10 − 2 Moles of Aluminum React with with 1.77

If 842 × 10^{− 2} Moles of Aluminum React with with 1.77