During a manufacturer process, a pocket of gases at 250 ° C formed a bubble inside of a liquid mass. The bubble had a volume of 325 mL at the time of it's formation. What is the volume of this bubble now that the product is in a 20 ° C storage facility?

Question

Quizplus · Accepted Answer

To find the volume of the gas at the new temperature, we can use Charles's Law, which states that $V_1/T_1 = V_2/T_2$, where $V$ is volume, $T$ is temperature in Kelvin, and the subscripts 1 and 2 refer to the initial and final states, respectively. First, convert the temperatures to Kelvin: $250°C + 273 = 523K$ and $20°C + 273 = 293K$. Then, solve for $V_2$: $325mL / 523K = V_2 / 293K$, which gives $V_2 = (325mL * 293K) / 523K ≈ 182mL$.

During a Manufacturer Process, a Pocket of Gases at 250