A piston is holding 125 mL of gases at a temperature of 300 K and a pressure of 2.39 atm. What is the volume of the gases if the temperature is increased to 500K and the pressure falls to 2.15 atm?

Question

Quizplus · Accepted Answer

Using the combined gas law, PV/T = constant, we can solve for the new volume:V2 = (P1 * V1 * T2) / (P2 * T1)V2 = (2.39 atm * 125 mL * 500 K) / (2.15 atm * 300 K)V2 = 231 mL

A Piston Is Holding 125 ML of Gases at a Temperature