A photon with a frequency of 2.1 × 10⁴ s^{− 1} has an energy of:

Question

Quizplus · Accepted Answer

The energy of a photon can be calculated using the formula E = hf, where h is Planck's constant (6.626 × 10^-34 J·s) and f is the frequency of the photon. Substituting the given frequency (2.1 × 10^14 s^-1) into the formula gives E = (6.626 × 10^-34 J·s) × (2.1 × 10^14 s^-1) = 1.39146 × 10^-19 J, which is approximately 1.4 × 10^-19 J, matching option C.

A Photon with a Frequency of 2