Given the following heat of formation values, calculate the heat of reaction for:
Na( s ) + Cl₂( g ) → NaCl( s )
Δ H_f values in kJ/mol for: Na( s ) = 0, Na( g ) = 108.7, Cl₂( g ) = 0, NaCl( s ) = − 411.0

Question

Quizplus · Accepted Answer

The heat of reaction can be calculated using the formula ΔH_reaction = ΣΔH_f(products) - ΣΔH_f(reactants). Given that ΔH_f(Na(s)) = 0, ΔH_f(Cl(g)) = 0, and ΔH_f(NaCl(s)) = -411.0 kJ/mol, the heat of reaction is simply the heat of formation of NaCl(s) since the reactants have a heat of formation of 0. Therefore, ΔH_reaction = -411.0 kJ.

Given the Following Heat of Formation Values, Calculate the Heat