Calculate the length\diameter ratio for the extended E. coli DNA (4 Å between adjacent nucleotides). E. coli DNA has 2 × 10⁶ bp. A) 4 × 10⁵ B) 1 × 10⁵ C) 3 × 10⁸ D) 3 × 10⁶

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The length of the extended E. coli DNA can be calculated by multiplying the number of base pairs (2 × 10^6 bp) by the distance between adjacent nucleotides (4 Å = 4 × 10^-10 m). This gives a length of 8 × 10^-4 m or 800 µm. The diameter of DNA is approximately 2 nm or 2 × 10^-9 m. Therefore, the length/diameter ratio is (8 × 10^-4 m) / (2 × 10^-9 m) = 4 × 10^5.

Calculate the Length\diameter Ratio for the Extended E