In the classical equation for respiration: Glucose + 6O₂ -- 6CO₂ + 6H₂O, the following molecules are found directly in the citric acid cycle: A) O₂ B) Glucose and O₂ C) CO₂ and H₂O D) all of these arae found directly in the citric acid cycle

Question

In the classical equation for respiration: Glucose + 6O₂ --> 6CO₂ + 6H₂O, the following molecules are found directly in the citric acid cycle: A) O₂ B) Glucose and O₂ C) CO₂ and H₂O D) all of these arae found directly in the citric acid cycle

Quizplus · Accepted Answer

COS1U1B12S1U1B0 (CO2) and HS1U1B12S1B0O (H2O) are products of the citric acid cycle, where CO2 is released as a waste product and water is used and produced in various steps of the cycle. Glucose and O2 (OS1U1B12S1U1B0) are not directly involved in the citric acid cycle; glucose is first broken down into pyruvate through glycolysis, and O2 is used in the electron transport chain, not directly in the citric acid cycle.

In the Classical Equation for Respiration