Three capacitors, a 12 μ F, a 20 μ F and a 30 μ F, are connected in series. What is the total capacitance?
A) 6 μ F
B) 62 μ F

Question

Quizplus · Accepted Answer

The total capacitance, $C_{total}$, of capacitors in series is given by the reciprocal of the sum of the reciprocals of the individual capacitances: $\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}$. Substituting the given values, $\frac{1}{C_{total}} = \frac{1}{12} + \frac{1}{20} + \frac{1}{30}$, solving this gives $C_{total} = 6 \mu F$.

Three Capacitors, a 12 μ F, a 20 μ F