An RLC series circuit has an applied voltage of 240 volts. R = 51 Ω , X_L = 100 Ω , and X_C = 32 Ω . The voltage drop across the inductor is 282 V. What is the voltage drop on the resistor? A) 143.82 V B) 192.73 V C) 382.5 V D) 422.4 V

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Quizplus · Accepted Answer

The impedance of the circuit is calculated using Z = √(R² + (X_L - X_C)²) = √(51² + (100 - 32)²) = √(51² + 68²) = √(2601 + 4624) = √7225 = 85 Ω. The current I = V/Z = 240/85 = 2.82 A. The voltage drop across the resistor V_R = I * R = 2.82 * 51 = 143.82 V.

An RLC Series Circuit Has an Applied Voltage of 240