Because the Hubble constant equals 70 km/s/Mpc, a galaxy with a recession velocity of 4,900 km/s would be a distance of ____ Mpc from Earth.
A) 0.014
B) 70
C) 4930
D) 4970
E) 343,000

Question

Quizplus · Accepted Answer

The Hubble constant (H0) relates the recession velocity (v) of a galaxy to its distance (d) from Earth through the formula v = H0 * d. Given v = 4,900 km/s and H0 = 70 km/s/Mpc, the distance d = v / H0 = 4,900 / 70 = 70 Mpc.

Because the Hubble Constant Equals 70 Km/s/Mpc, a Galaxy with a Recession