Consider the following reaction: 3NO₂( g )+ H₂O( l ) → 2HNO₃( aq )+ NO( g ). What quantity (L)of NO₂is required to completely react with 125 g of water? Assume that the gases are at standard temperature and pressure; hence, 1.00 mole occupies 22.4 L of volume.

Question

Quizplus · Accepted Answer

To find the volume of NO₂ required, first calculate the moles of H₂O: 125 g H₂O × (1 mol/18.02 g) = 6.94 mol H₂O. According to the balanced equation, 3 moles of NO₂ react with 1 mole of H₂O. Therefore, 6.94 mol H₂O requires 3 × 6.94 = 20.82 mol NO₂. At STP, 1 mole of gas occupies 22.4 L, so 20.82 mol NO₂ × 22.4 L/mol = 466.37 L, which rounds to 466 L.

Consider the Following Reaction: 3NO2( G )+ H2O( L )

Consider the Following Reaction: 3NO₂( G )+ H₂O( L )