If liquid mercury and oxygen combine to make mercury(II)oxide, what is the percentage yield of HgO if 350.0 g of Hg( l )react with 150.0 g of O₂( g )to produce 272.3 g of the product?

Question

Quizplus · Accepted Answer

The theoretical yield of HgO can be calculated using stoichiometry. The balanced equation is 2Hg + O2 → 2HgO. The molar mass of Hg is 200.59 g/mol, so 350.0 g of Hg is 1.745 mol. The molar mass of O2 is 32.00 g/mol, so 150.0 g of O2 is 4.688 mol. Hg is the limiting reactant. The theoretical yield of HgO is 1.745 mol × 216.59 g/mol = 377.8 g. The percentage yield is (272.3 g / 377.8 g) × 100% = 72.07%.

If Liquid Mercury and Oxygen Combine to Make Mercury(II)oxide, What