If 92.8 g of sodium nitrite is dissolved in 2.3 L of water, the resulting solution has a molarity of:

Name: If 92.8 g of sodium nitrite is dissolved in 2.3 L of water, the resulting solution has a molarity of:
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Quizplus · Accepted Answer

To find the molarity, divide the number of moles of solute by the volume of the solution in liters. The molar mass of sodium nitrite (NaNO2) is approximately 69 g/mol. Therefore, 92.8 g corresponds to 92.8 g / 69 g/mol = 1.3449 mol. The molarity is then 1.3449 mol / 2.3 L = 0.58 M.

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