If a 136.51 g Al rod (c = 0.900 J\g ° C)is at 100.0 ° C and placed into 250.0 g of water at 21.8 ° C, what is the temperature of the system (rod + water)at equilibrium assuming no losses to the surroundings? Assume the specific heat of water to be 4.18 J\g ° C.

Question

Quizplus · Accepted Answer

The heat lost by the Al rod equals the heat gained by the water. Using the formula $m \cdot c \cdot \Delta T$ for both substances and setting them equal, solve for the final temperature. The calculation shows the equilibrium temperature is approximately 30 °C.

If a 13651 G Al Rod (C = 0