Given the following heat of formation values, calculate the heat of reaction for:
Na( s ) + Cl ₂( g ) → NaCl( s ) .
Δ H _fvalue in kJ\mol for Na( s ) is 0, for Na( g ) is 108.7, for Cl ₂( g ) is 0, and for NaCl( s ) is − 411.0.

Question

Quizplus · Accepted Answer

The heat of reaction is equal to the difference between the heat of formation of the products and the heat of formation of the reactants. In this case, the heat of formation of the products is -411.0 kJ and the heat of formation of the reactants is 0 kJ. Therefore, the heat of reaction is -411.0 kJ.

Given the Following Heat of Formation Values, Calculate the Heat