How many grams of N₂ are required to completely react with 3.03 grams of H₂ for the following balanced chemical equation? N₂ + 3H₂ → 2NH₃

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Quizplus · Accepted Answer

To balance the equation, we need 1 mole of N₂ for every 3 moles of H₂. Therefore, the mole ratio of N₂ to H₂ is 1:3.Given 3.03 grams of H₂, we can calculate the number of moles of H₂:```moles of H₂ = mass / molar mass = 3.03 g / 2.02 g/mol = 1.5 mol```According to the mole ratio, we need 1/3 mole of N₂ for every mole of H₂. Therefore, the number of moles of N₂ required is:```moles of N₂ = (1/3) * moles of H₂ = (1/3) * 1.5 mol = 0.5 mol```Finally, we can convert the moles of N₂ to grams:```mass of N₂ = moles * molar mass = 0.5 mol * 28.02 g/mol = 14.0 g```Therefore, 14.0 grams of N₂ are required to completely react with 3.03 grams of H₂.

How Many Grams of N2 Are Required to Completely React

How Many Grams of N₂ Are Required to Completely React