Determine the efficiency of a solar system which uses a focusing system covering 300 m² and produces 50 kW of power. The solar power available is 900 W\m².

Question

Quizplus · Accepted Answer

The efficiency is calculated by dividing the output power by the input power. The input power is the solar power available (900 W/m²) multiplied by the area (300 m²), which equals 270,000 W or 270 kW. The output power is 50 kW. Efficiency = (50 kW / 270 kW) * 100% = 18.52%, which is closest to 18%.

Determine the Efficiency of a Solar System Which Uses a Focusing