Determine the efficiency of a solar system which uses a 75 heliostats with an area of 3.0 m² and produces 25 kW of power. The solar power available is 1100 W\m².

Question

Quizplus · Accepted Answer

The efficiency of the solar system is given by the ratio of the power produced to the power available. The power available is the product of the solar power available and the area of the heliostats. The power produced is 25 kW. Therefore, the efficiency is:$$\eta = \frac{P_{produced}}{P_{available}} = \frac{25 kW}{1100 W/m^2 	imes 75 	imes 3.0 m^2} = 10%$$

Determine the Efficiency of a Solar System Which Uses a 75