How many grams of carbon dioxide are produced when 18.5 moles of oxygen react with excess acetylene according to the given equation?

2 C₂H₂ + 5 O₂(g) → 4 CO₂ + 2 H₂O

Question

How many grams of carbon dioxide are produced when 18.5 moles of oxygen react with excess acetylene according to the given equation? 2 C₂H₂ + 5 O₂(g) → 4 CO₂ + 2 H₂O

Quizplus · Accepted Answer

From the balanced equation, we see that for every 5 moles of oxygen consumed, 4 moles of carbon dioxide are produced. Therefore, we can set up a proportion:

5 mol O2/4 mol CO2 = 18.5 mol O2/x mol CO2

Solving for x, we get:

x = (18.5 mol O2)(4 mol CO2/5 mol O2) = 14.8 mol CO2

Finally, we can convert moles of carbon dioxide to grams using the molar mass of CO2:

14.8 mol CO2 x (44.01 g CO2/mol) = 651.2 g CO2

Therefore, the answer is C) 651.2 grams.

How Many Grams of Carbon Dioxide Are Produced When 18