What is the efficiency of a solar system that uses a focusing system covering an area of 300 m ² and produces 50 kW of power? The solar power available is 900 W/m ² .

Question

Quizplus · Accepted Answer

The total solar power available for the 300 m² area is:

P = 900 W/m² x 300 m² = 270,000 W

If the system produces 50 kW of power, then its efficiency is:

Efficiency = (Power produced / Total solar power available) x 100%
Efficiency = (50,000 W / 270,000 W) x 100%
Efficiency = 0.1852 x 100% 
Efficiency = 18.52%

Therefore, the correct choice is B.

What Is the Efficiency of a Solar System That Uses