What is the efficiency of a solar system that uses 75 heliostats with an area of 3.0 m ² and produces 25 kW of power? The solar power available is 1100 W/m ² .

Question

Quizplus · Accepted Answer

The efficiency of the solar system is given by:$$\eta = \frac{P_{out}}{P_{in}}$$where:* $P_{out}$ is the power output of the solar system* $P_{in}$ is the power input to the solar systemThe power input to the solar system is given by:$$P_{in} = A 	imes I$$where:* $A$ is the area of the heliostats* $I$ is the solar power availableThe power output of the solar system is given by:$$P_{out} = 25 	ext{ kW}$$The area of the heliostats is given by:$$A = 75 	imes 3.0 	ext{ m}^2 = 225 	ext{ m}^2$$The solar power available is given by:$$I = 1100 	ext{ W/m}^2$$Therefore, the efficiency of the solar system is:$$\eta = \frac{25 	ext{ kW}}{225 	ext{ m}^2 	imes 1100 	ext{ W/m}^2} = 10.10%$$

What Is the Efficiency of a Solar System That Uses