A basketball is inflated to a pressure of 1.50 atm in a garage at a temperature of 20.0 ° C . What will be the pressure of the basketball outside where the temperature is − 5.00 ° C?

A) 0.375 atm
B) 1.37 atm
C) 1.42 atm
D) 1.67 atm
E) 3.01 atm

Question

A basketball is inflated to a pressure of 1.50 atm in a garage at a temperature of 20.0 ° C . What will be the pressure of the basketball outside where the temperature is − 5.00 ° C?
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A) 0.375 atm
B) 1.37 atm
C) 1.42 atm
D) 1.67 atm
E) 3.01 atm

Quizplus · Accepted Answer

We can use the combined gas law to solve for the final pressure:

(P1/T1) = (P2/T2)

We will need to convert the temperatures to Kelvin:
T1 = 20.0 + 273 = 293 K
T2 = −5.00 + 273 = 268 K

Substituting the given values:
(1.50 atm/293 K) = (P2/268 K)

Solving for P2:
P2 = (1.50 atm/293 K) * 268 K
P2 = 1.37 atm

Therefore, the pressure outside will be 1.37 atm. The answer is B.

A Basketball Is Inflated to a Pressure of 1