A sample of gas occupies 30.0 L at 0 ° C and 1 atm. What temperature will the same gas have in a 22.5 L container with a pressure of 3.5 atm?
A) 212 ° C
B) 284.2 ° C
C) 386 ° C
D) 443.64 ° C
E) 516 ° C

Question

Quizplus · Accepted Answer

We can use the combined gas law to solve this problem:

(P1V1/T1) = (P2V2/T2)

where:
P1 = 1 atm
V1 = 30.0 L
T1 = 0 °C + 273.15 = 273.15 K (converted to Kelvin)
P2 = 3.5 atm
V2 = 22.5 L
T2 = ?

Plugging in the values and solving for T2:

(1 atm)(30.0 L)/(273.15 K) = (3.5 atm)(22.5 L)/T2

T2 = (3.5 atm)(22.5 L)(273.15 K)/(1 atm)(30.0 L) = 443.64 K

Converting back to Celsius:

T2 = 443.64 K - 273.15 = 170.49 °C

Therefore, the answer is D) 443.64 °C.

A Sample of Gas Occupies 30