A series circuit contains a total resistance of 100 .If the circuit has three resistors and one of the resistors is 40 ,what is the combined resistance of the last two resistors?
A) 60
B) 2.5
C) 140
D) 0.04

Question

A series circuit contains a total resistance of 100  .If the circuit has three resistors and one of the resistors is 40  ,what is the combined resistance of the last two resistors?
A) 60 
B) 2.5 
C) 140 
D) 0.04

Quizplus · Accepted Answer

According to Kirchhoff's laws regarding series circuits,total resistance is equal to the sum of all resistors in the circuit.If the circuit has three resistors,total resistance = A + B + C.Therefore,100 = A + B + C.If one resistor is 40 11ea355f_929f_e970_b24d_e50d7ae36f8c_TB1879_11 ,then 100 = 40 + B + C and the sum of B + C must equal 60 11ea355f_929f_e971_b24d_15fec7093368_TB1879_11 .

A Series Circuit Contains a Total Resistance of 100