In a random population,16% of the population is homozygous for a particular trait.What percentage of the same population is heterozygous for that particular trait?

Question

Quizplus · Accepted Answer

Using the Hardy Weinberg formula,(p + q)² = 1.0 therefore the square root of 16 is 4 and 4 + 6 = 1.Since the expanded formula is p² + 2pq + q² = 1.0,then 2pq is the heterozygous population,which is 2 × 4 × 6 = 48.

In a Random Population,16% of the Population Is Homozygous for a Particular