specific heat capacity of ice = 2,000 J/kg-°C latent heat of fusion of water = 334,000 J/kg
specific heat capacity of water = 4,000 J/kg-°C
A 1 kg block of ice is removed from a freezer where its temperature was -10°C. The amount of heat absorbed by the ice as it warms to 0°C is
A) 2,000 J.
B) 4,000 J.
C) 20,000 J.
D) 40,000 J.
E) 334,000 J.

Question

specific heat capacity of ice = 2,000 J/kg-°C      latent heat of fusion of water = 334,000 J/kg
     specific heat capacity of water = 4,000 J/kg-°C
A 1 kg block of ice is removed from a freezer where its temperature was -10°C. The amount of heat absorbed by the ice as it warms to 0°C is
A) 2,000 J.
B) 4,000 J.
C) 20,000 J.
D) 40,000 J.
E) 334,000 J.

Quizplus · Accepted Answer

The amount of heat absorbed by the ice as it warms from -10°C to 0°C can be calculated using the specific heat capacity of ice:

Q1 = m * c * ΔT1 
Q1 = 1 kg * 2,000 J/kg-°C * (0°C - (-10°C)) 
Q1 = 20,000 J

Next, the amount of heat absorbed by the ice as it melts into water at 0°C can be calculated using the latent heat of fusion of water:

Q2 = m * Lf 
Q2 = 1 kg * 334,000 J/kg 
Q2 = 334,000 J

Finally, the amount of heat absorbed by the water as it warms from 0°C to its final temperature can be calculated using the specific heat capacity of water:

Q3 = m * c * ΔT2 
Q3 = 1 kg * 4,000 J/kg-°C * (Tf - 0°C)

Since the final temperature is not given, we can assume it stays at 0°C. Therefore, ΔT2 = 0°C, and Q3 = 0 J.

The total amount of heat absorbed by the ice can be found by adding the three calculated values:

Qtotal = Q1 + Q2 + Q3 = 20,000 J + 334,000 J + 0 J = 354,000 J

Therefore, the correct answer is C) 354,000 J.

Specific Heat Capacity of Ice = 2,000 J/kg-°C Latent