For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: ( T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
If the Kelvin temperature of an object is doubled, the amount of radiant energy emitted each second is twice the original amount.

Question

For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature:  ( T in kelvins) 
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters, T in kelvins) 
Assume an object is emitting blackbody radiation. 
If the Kelvin temperature of an object is doubled, the amount of radiant energy emitted each second is twice the original amount.

Quizplus · Accepted Answer

The Answer of For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature:  ( T in kelvins) 
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters, T in kelvins) 
Assume an object is emitting blackbody radiation. 
If the Kelvin temperature of an object is doubled, the amount of radiant energy emitted each second is twice the original amount.

For a Body Emitting Blackbody Radiation, the Total Power Emitted