For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: ( T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
The peak of a body's blackbody radiation curve shifts upward as the temperature of the body increases.

Question

For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature:  ( T in kelvins) 
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters, T in kelvins) 
Assume an object is emitting blackbody radiation. 
The peak of a body's blackbody radiation curve shifts upward as the temperature of the body increases.

Quizplus · Accepted Answer

According to Wien's displacement law, the wavelength of the peak of the blackbody radiation curve is inversely proportional to the absolute temperature of the body. As the temperature increases, the wavelength of the peak decreases and shifts toward the shorter (higher frequency) end of the electromagnetic spectrum.

For a Body Emitting Blackbody Radiation, the Total Power Emitted