For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: ( T in kelvins)
And the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
As the temperature of an object increases, the wavelength of the brightest light emitted
A) increases.
B) decreases.
C) doesn't change.
D) depends on the composition of the body.
E) depends on the size of the body.

Question

For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature:  ( T in kelvins)
And the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
As the temperature of an object increases, the wavelength of the brightest light emitted
A) increases. 
B) decreases. 
C) doesn't change. 
D) depends on the composition of the body. 
E) depends on the size of the body.

Quizplus · Accepted Answer

According to the second law mentioned above, the wavelength of the emitted radiation with the highest intensity is inversely proportional to the body's absolute temperature. Therefore, as the temperature of the object increases, the wavelength of the highest intensity radiation must decrease. This relationship is known as Wien's displacement law.

For a Body Emitting Blackbody Radiation, the Total Power Emitted