For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature:
( T in kelvins)
And the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:
(
in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
If the Kelvin temperature of a body is doubled, the wavelength of the most intense light is ____________ the wavelength originally of the most intense light.
A) 1/16th
B) half
C) the same as
D) 2 times
E) 16 times
Correct Answer:
Verified
Q65: The type of EM radiation that causes
Q67: The lowest frequency visible light is
A)violet.
B)red.
C)blue.
D)green.
E)yellow.
Q70: FM radio only operates in the frequency
Q73: Why would a decrease in the amount
Q75: The type of EM radiation that has
Q76: How can microwave ovens heat food more
Q77: Which of the following is not a
Q78: The type of EM radiation that has
Q79: AM radio stations have greater range than
Q98: About how hot does something have to
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents